Does .9999999 Repeating = 1?

Asami Sato | Newbie
 
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The answer to this question alluded my creators, and now I must know.


rC | Mythic Inconceivable!
 
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ayy lmao
Of course not, two different numbers can't be equal.


R o c k e t | Mythic Smash Master
 
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I neither fear, nor despise.
It is close, VERY close.
But no.

Unless you round it up of course.


Turkey | Mythic Inconceivable!
 
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Oh my sweet lord jesus christ please don't do this.


 
Alternative Facts
| Mythic Forum Ninja
 
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Of course not, two different numbers can't be equal.

50/50

Either they are equal, or they aren't.


rC | Mythic Inconceivable!
 
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ayy lmao
Oh my sweet lord jesus christ please don't do this.
It's pretty much common knowledge that they aren't equal.


rC | Mythic Inconceivable!
 
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ayy lmao
Of course not, two different numbers can't be equal.

50/50

Either they are equal, or they aren't.
Exactly.


Jocephalopod | Mythic Inconceivable!
 
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the answer is in this simple equation



Epsira | Legendary Invincible!
 
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The number "0.9999..." can be "expanded" as:

0.9999... = 0.9 + 0.09 + 0.009 + 0.0009 + ...

In other words, each term in this endless summation will have a "9" preceded by some number of zeroes. This may also be written as:

0.999... = 9/10 + (9/10)(1/10)^1 + (9/10)(1/10)^2 + (9/10)(1/10)^3 + ...

That is, this is an infinite geometric series with first term a =  9/10 and common ratio r =  1/10. Since the size of the common ratio r is less than 1, we can use the infinite-sum formula to find the value:

0.999... = (9/10)[1/(1 - 1/10)] = (9/10)(10/9) = 1

So the formula proves that 0.9999... = 1.

from Purplemath


Edit: Part of the answer didn't copy
http://www.purplemath.com/modules/howcan1.htm
Last Edit: December 10, 2014, 09:16:49 PM by Epsira


Turkey | Mythic Inconceivable!
 
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Oh my sweet lord jesus christ please don't do this.
It's pretty much common knowledge that they aren't equal.



rC | Mythic Inconceivable!
 
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ayy lmao
Oh my sweet lord jesus christ please don't do this.
It's pretty much common knowledge that they aren't equal.


Are you trying to say that you know more about math than me, being in high school calculus?