Quote from: Winy on May 25, 2016, 01:42:53 PM

Quote from: Desty on May 25, 2016, 01:39:33 PM

Quote from: Ender on May 25, 2016, 01:37:20 PM

Quote from: Winy on May 25, 2016, 11:25:36 AM

Spoiler

a). 5^x = 3

You just take the log of both sides and solve for x

x * Log(5) = Log(3)

So x is Log(3)/Log(5)

If they want an approximate decimal, apparently that's about 0.6826

b). x^1/3 = 2

Just take the 1/3 root of 2, which is just the first root of 2³

So it's just 8.

beat me too it

Oh my god, what is going on

Is it international mispelling day or something? Things are starting to feel surreal

*Misspelling

Oh no, it's contagious

Can you do question 9?
I'm trying to figure out how to solve it

What is it asking for?

Why are you all doing Desty's homework for him?

you should be able to solve this

Okay, got it. I'm gonna write the square roots as 1/2 powers, because obviously I can't actually put in a square root symbol.

((x^1/2 + 3^1/2)² - (x + 3))/2

Square that first term, and that's really the hardest part of simplifying it, you just FOIL it (That's what we called it, I've heard other people use a different acronym). Also, writing this out is kind of a pain, so if you need me to explain something more clearly, I will.

So it becomes (x + 2 * x^1/2 * 3^1/2 + 3 - (x + 3))/2

Distribute the negative sign,

(x + 2 * x^1/2 * 3^1/2 + 3 - x - 3)/2

The threes cancel, as do the x terms.

So then you're left with

2(x^1/2 * 3^1/2)/2

The 2s cancel, as well.

And the whole problem simplifies nicely to

x^1/2 * 3^1/2

Or just, "The square root of x times the square root of 3."

Okay, got it. I'm gonna write the square roots as 1/2 powers, because obviously I can't actually put in a square root symbol.

((x^1/2 + 3^1/2)² - (x + 3))/2

Square that first term, and that's really the hardest part of simplifying it, you just FOIL it (That's what we called it, I've heard other people use a different acronym). Also, writing this out is kind of a pain, so if you need me to explain something more clearly, I will.

So it becomes (x + 2 * x^1/2 * 3^1/2 + 3 - (x + 3))/2

Spoiler

Distribute the negative sign,

(x + 2 * x^1/2 * 3^1/2 + 3 - x - 3)/2

The threes cancel, as do the x terms.

So then you're left with

2(x^1/2 * 3^1/2)/2

The 2s cancel, as well.

And the whole problem simplifies nicely to

x^1/2 * 3^1/2

Or just, "The square root of x times the square root of 3."

nvm got it

Thaaaank you, Mathemagician

>expecting me to do math when I'm now on summer vacation

lolnothx

If you do this (x^4/6 -1)/ x^3/6 I'll be super happy

That's okay